Key frequency analysis (short keys have leading "3"'s trimmed)
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12Me21Created:
Notice how 3 (the most common character) is never in the first position.
Keys with fewer than 8 characters just had 3's at the beginning which were trimmed off. KXJJ333 = 3KXJJ333, for example.
shh the illuminati heard that
if you type a key that's less than 8 digits with 3s equal to the amout of digits less than 8 before the key it will download the program. (so if you have a program which has a key of AABBCCD you can type 3AABBCCD instead and it will download it)
So, what's this useful for...?
It's useful in the case where you want to type extra threes so you can have the satisfaction of supporting the illuminati adding random garbage to yet another location.
Take a key with less than 8 digits
Add 3's to the front to make it 8 digits
You now have an 8 digit key
Any key containing 8 digits can have up to 6 of any digits added to the end of that key
And it'll still accept it
The public key AABBCC
=3AABBCC
=33AABBCC
=33AABBCC_HELLO
=33AABBCCDDEEFF
Getting the smallest public key is all about getting multiple 3's in a row in the beginning
Interesting find
So the characters 0, I (uppercase i), O, U, -, and _ never appear in keys, which means there are exactly 32 characters that do appear in the keys:
3, E, 4, K, D, N, X, V, J, 2, Q, 5, 8, A, R, S, Y, C, P, 7, W, Z, H, B, 1, F, M, L, 9, 6, G, T
Considering that keys are in base-32, with 3 being unscrambled to 0, we can use the position frequency in the graph to estimate the order of unscrambling keys, to get their base-10 index
Replying to:Simeon
So the characters 0, I (uppercase i), O, U, -, and _ never appear in keys, which means there are exactly 32 characters that do appear in the keys:
3, E, 4, K, D, N, X, V, J, 2, Q, 5, 8, A, R, S, Y, C, P, 7, W, Z, H, B, 1, F, M, L, 9, 6, G, T
Considering that keys are in base-32, with 3 being unscrambled to 0, we can use the position frequency in the graph to estimate the order of unscrambling keys, to get their base-10 index
How many keys did you use to make that graph?
Can you share the database with us too?
Replying to:Simeon
So the characters 0, I (uppercase i), O, U, -, and _ never appear in keys, which means there are exactly 32 characters that do appear in the keys:
3, E, 4, K, D, N, X, V, J, 2, Q, 5, 8, A, R, S, Y, C, P, 7, W, Z, H, B, 1, F, M, L, 9, 6, G, T
Considering that keys are in base-32, with 3 being unscrambled to 0, we can use the position frequency in the graph to estimate the order of unscrambling keys, to get their base-10 index
About 1000 I think.
https://pastebin.com/raw/PFugbCGu
There are a few duplicates
Replying to:Simeon
Take a key with less than 8 digits
Add 3's to the front to make it 8 digits
You now have an 8 digit key
Any key containing 8 digits can have up to 6 of any digits added to the end of that key
And it'll still accept it
The public key AABBCC
=3AABBCC
=33AABBCC
=33AABBCC_HELLO
=33AABBCCDDEEFF
Getting the smallest public key is all about getting multiple 3's in a row in the beginning
Interesting find
ALREADY EXPLAINED ON i's COMMENT BY ME
to quote myself:"if you type a key that's less than 8 digits with 3s equal to the amout of digits less than 8 before the key it will download the program. (so if you have a program which has a key of AABBCCD you can type 3AABBCCD instead and it will download it)"