FOR I=0 TO LEN(ARY)-1 'old FOR I=0 TO LAST(ARY) 'newHowever, they have neglected to include a FIRST function, to find the first index in the array. I'm sure FIRST will be added soon in an update, but until then, here is a user defined function you can use:
DEF FIRST(ARY) RETURN LAST(ARY)-LEN(ARY)+1 ENDExample usage:
FOR I=FIRST(ARY) TO LAST(ARY) PRINT ARY[I] NEXT